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Return only the best place for each article

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Arne Schlüter 2015-02-07 19:14:13 +01:00
commit 7846dad0a8
1 changed files with 29 additions and 18 deletions
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37
server.py
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@ -29,28 +29,39 @@ def index():
@bottle.get("/articles/")
def articles():
conn = sqlite3.connect('violence.db')
c = conn.cursor()
c = c.execute("""
SELECT article.id, article.date, article.place, article.description, category.name,
location.confidence, location.lat, location.lng, location.match, location.returned_place
cursor = conn.cursor()
l = cursor.execute("""
SELECT location.lat, location.lng, location.returned_place, location.article_id
FROM location
ORDER BY location.confidence DESC, location.id ASC
""")
locations = {}
for location in l.fetchall():
# check if we already have entries for the article_id
if not locations.get(location[3]):
locations[location[3]] = (location[0], location[1], location[2])
c = cursor.execute("""
SELECT article.id, article.date, article.place, article.description, category.name
FROM article
JOIN category ON article.id = category.article_id
JOIN location ON article.id = location.article_id
""")
articles = []
for article in c.fetchall():
article_id = article[0]
if locations.get(article_id):
articles.append({
"id": article[0],
"id": article_id,
"date": article[1],
"place": article[2],
"desc": article[3],
"cat": article[4],
"conf": article[5],
"lat": article[6],
"lng": article[7],
"match": article[8],
"returned_place": article[9]
"description": article[3],
"category": article[4],
"lat": locations[article_id][0],
"lng": locations[article_id][1],
"place": locations[article_id][2]
})
conn.close()
return json.dumps(articles)